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Lobstah

Question about the "Time:" value displayed as a media capacity . . .

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First off . . . N I C E piece of software LUK!

Curious about the time displayed along with number of sectors, etc. Am I correct in assuming that 510 minutes of recording time on a 4.7gb blank disk is for recording audio?

If so, is it possible to display the recording time for SP Mpeg2 video? . . . or maybe both? Since 510 is already calculated, there's probably a constant that could be used to derive the video time.

Spent an hour searching the forum before posting this, hope I didn't miss something.

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The problem is that MPEG2 is variably compressed. You can have a full DVD-5 that has any where from 60min to 180min of video. It also depends on what type of audio you use and other factors. I also think that your SP definition will vary between hardware and software. I think it would seem more confusing to some users to see this method. At the same time, the amount of 44.1k 16b CDA audio I can fit on a DVD has much meaning either. Maybe just don't show the time for anything other than CD?

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Thanks for the feedback.

 

You are right about the variable bitrate, but the audio has the same problem. I was just wondering since someone came up with a stardard audio bitrate to calculate from, that the same could be done for video.

For instance, using a blank DVD-RAM in my Panasonic, the disk-info screen tells me I have 2 hours of video that I can record in Standard Play mode. If I change modes, it adjust the time accordingly.

Now, when I remove the DVD-RAM from the living room and place it in my PC (Samsung DVD recorder), it tells me I have 510 minutes. And if I have a 1-hour recording on it, the Panasonic tells me I have 1 hour of space left, while the Samsung under IB tells me I have 250 minutes of space left.

I was hoping that we could select a bitrate as a benchmark . . . say . . . a fixed bitrate that would allow a 2-hour recording on 1 single-sided DVD, and calculate video time from there.

It really isn't a big deal for me, I was just curious about how the "510" is being calculated, and what it actually represents.

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It really isn't a big deal for me, I was just curious about how the "510" is being calculated, and what it actually represents.

That time is calculated based on a 1X data CD-ROM read speed, which has 2.048 bytes per sector read at 75 sectors/second, resulting in 153.600 bytes read per second.

 

4.706.074.624 / 153.600 = ~30638,5 seconds / 60 = ~510,64 minutes

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Thank you for the info. That definitely answers my question.

It's what I suspected, but I wasn't really sure until you supplied the numbers.

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