I want to make a bootable ISO with Platform Id = UEFI. If I use the command line parameter /BOOTPLATFORMID 3 which I found here in an old posting, the Platform Id remains 80x86. The complete command line options I'm using are
/MODE BUILD /BUILDOUTPUTMODE IMAGEFILE /SRC "F:\BootISOs\Inject" /OVERWRITE YES /ROOTFOLDER YES /DEST "F:\BootISOs\test.iso" /VOLUMELABEL Injected /MakeImageBootable 1 /BOOTIMAGE F:\BootISOs\Inject\Boot\efisys.bin /BOOTEMUTYPE 0 /BOOTSECTORSTOLOAD 2880 /BOOTPLATFORMID 3
The reason I want this id is I'm adding drivers to a WinPE ISO for use with Easy2Boot. Without id=UEFI, Ventoy under Easy2Boot doesn't work. If I don't include the BOOTPLATFORMID option, I can set it manually, but that sort of defeats the desire to make the whole process script driven.
Thanks.
