shadowcaster Posted October 2, 2008 Posted October 2, 2008 (edited) This isn't an imgburn question directly. When I burn a dl disc and then use Plextools to check for pi/po errors, the error rate is always greater from 0 to ~4gb then it is from ~4gb to the end. So, my question is, which layer is actually burned first, the top or bottom ? Logic would tell me that the second layer is burned first but I don't know. Edit: Ok, found the answer to the second part. The top layer (closet to the disc surface) is burned first. So, why does this layer always have more pi errors than the 2nd layer ? (Plextor 760a, VB DL/Singapore @ 2.4x) Edited October 2, 2008 by shadowcaster
blutach Posted October 3, 2008 Posted October 3, 2008 Layer 0 is burned first from the hub to the outside then layer 1 from outside in. Layer 1 always has significantly more PI errors since the laser has to "read through data" on layer 0 to get to it. If your burn is within ECMA specs, you should not be worried. Regards
Handler Posted October 3, 2008 Posted October 3, 2008 (edited) Layer 0 is burned first from the hub to the outside then layer 1 from outside in. Layer 1 always has significantly more PI errors since the laser has to "read through data" on layer 0 to get to it. If your burn is within ECMA specs, you should not be worried. When Shadowcaster wrote, "the error rate is always greater from 0 to ~4gb then it is from ~4gb to the end", I believe Shadowcaster was under the impression that the (lower) Layer 1 was burned first. If you look HERE you can see what Shadowcaster probably meant to ask. Edited October 3, 2008 by Handler
shadowcaster Posted October 3, 2008 Author Posted October 3, 2008 Layer 0 is burned first from the hub to the outside then layer 1 from outside in. Layer 1 always has significantly more PI errors since the laser has to "read through data" on layer 0 to get to it. If your burn is within ECMA specs, you should not be worried. Regards Handler is correct. What I'm experiencing is exactly the opposite of your post. Layer 0 is the one with greater errors (as seen in the scan). It's not a problem, I was just curious why this was the case.
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